SuperRembo Posted January 10, 2006 Report Share Posted January 10, 2006 (edited) Varat kads man izpalidzeet plz so uzdevumu izpildiiit, ka nemokos nevaru ar tam tabulam kur rombi paralelogrami sakums beigas ^^ Nu kas ar so lietu saskarusies zinasiet. Tatad pats uzdevums: Uzzimet sekojosu algoritmu. Programma pieprasa ievadit 3 skaitlus. Pec tam izvada uz ekrana videjo pec lieluma. Luk cik es zinu uz 99% ka pareizi ^^ Edited January 10, 2006 by SuperRembo Link to comment Share on other sites More sharing options...
EDD Posted January 10, 2006 Report Share Posted January 10, 2006 LOLOMGWTFROFLMAOPWNT. pat ja man (pat man) par kautkādu aizvēsturisku paskālu prasītu, es varētu atbildēt. this one's gotta be a real piece of cake. Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 Palidziet plzzz kaads, ka so lidz galam aizvest Link to comment Share on other sites More sharing options...
Pulkvedis Posted January 10, 2006 Report Share Posted January 10, 2006 tev nevajag uzreiz uzrakstiit programmu tam shitam? beigais slinkums taadu suudu ziimeet.. Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 Man vel teorija, kad teoriju saja lieta iziesim tad kersimies pie pascal, bet tas bus vel pec laicinja Tapec man sobrid japrot so lietu zimet a skolotajs sadu iedeva un nebij nekadu uzdevumu, pasam logiski jaizdoma ka kas varetu buut. Es netiku gala tante google saja lieta kuru man uzdevumu vajag diezvai palidzes. Tapec es griezos GIGN jo sis ir manas 2 majas. Link to comment Share on other sites More sharing options...
Kavacky Posted January 10, 2006 Report Share Posted January 10, 2006 Nu moš padomā, kā starp 3 skaitļiem atrast to, kurš ir vidējais, izmantojot "ir lielāks/mazāks par? -> jā/nē". Un tad arī varēsi uzzīmēt. Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 Es so nesaproti ja butu uzzimet 2 skaitlu summu vai 3 skaitlu tad vel varetu tikt gala vai ari 2 cilveku vards gadi un lai proga uz ekrana izmet Janis ir par 5 gadi vecaks. Bet ar skaitliem siem lai videjo atrod es nekaa nezinu ( man nav piemera neviena kur butu kaut kas videjais jaatrod tapec nezinu ka so uzdevumu darit . Link to comment Share on other sites More sharing options...
Kavacky Posted January 10, 2006 Report Share Posted January 10, 2006 Bļeģ, lāpstas kātam ir spēcīgāka loģika par tavējo. Nu kā tu vari pateikt pats, kurš skaitlis vidējais? Ir lielāks par vienu skaitli? Ir mazāks par otru skaitli? => Ir vidējais. Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 Es kamer to neredzeju dzivaja, no teikta nesapratisu, man vajag zimejumu gatavu redzet si uzdevuma. Lai es varetu zinat ar parejiem ka buut. Link to comment Share on other sites More sharing options...
macho Posted January 10, 2006 Report Share Posted January 10, 2006 mamma mia. Link to comment Share on other sites More sharing options...
EDD Posted January 10, 2006 Report Share Posted January 10, 2006 PSC, es tikai tagad sapratu, ka tas ir TIK vienkaarshi. PSC PSC PSC PSC PSC PSC PSC. es biju domaajis, ka jaaizreekjina tas videejais, nevis tikai jaapasaka, kursh peec veertiibas ir videejais. PSC PS PC PSC Link to comment Share on other sites More sharing options...
moby Posted January 10, 2006 Report Share Posted January 10, 2006 boot.lv forums, tur ari par programmesanu ir daudz un tur labi paskaidros... Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 Luk pieraksti ko pa 1 stundu panjemam, please palidziet kads atrisinat, P.S ja tas bus no GIGN klana nosutisu GIGN 1ls sai pat nakt par uzdevumu. Alinjam bus gana Picture1.rar Link to comment Share on other sites More sharing options...
macho Posted January 10, 2006 Report Share Posted January 10, 2006 man tāpat pietiek ko darīt. Tiec vien galā pats. Nekā sarežģīta tur nav. Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 p.s es taja boot.lv jau atradu vel vienu dzeku ar lidzigu problemu ari prasa ka uzdevumu izpildit tikai daudzi x3 nezin Link to comment Share on other sites More sharing options...
SuperRembo Posted January 10, 2006 Author Report Share Posted January 10, 2006 varbut sadi pierakstit Taisnsturi z=a+b+c:3 ?????? Link to comment Share on other sites More sharing options...
krish Posted January 11, 2006 Report Share Posted January 11, 2006 blood tak padomā ar smadzenēm pidiņš nelaimīgais Link to comment Share on other sites More sharing options...
Dr. Pain Posted January 11, 2006 Report Share Posted January 11, 2006 blood, tikko uzziimeeju minuutes laikaa (nu labi, paarspiileeju, pusminuutes laikaa) to ziimeejumu. Tur ne suuda taksh nav. Vienkaarshi ziimee un viss. Tur jaadomaa galiigi nav. Ziimee. Saliidzini visus skaitljus un viss buus ok. p.s. ej taksh uz parasto skolu, jo redzams, ka programeeshana galiigi nav tava stipraa puse. p.p.s. kaa man kretinee tie pidinji, kas iedomaajas, man patiik speeleet cs, tad jau vareetu maaciities kauko saistiitu ar datoriem p.p.p.s. ziimeejumu izmetu aaraa, lai tu pats vareetu padomaat ar galvu Link to comment Share on other sites More sharing options...
Dj_erix Posted January 11, 2006 Report Share Posted January 11, 2006 (edited) Neko nejēdzu no programmēšanas, bet pat es izpratu Bet tas laikam tikai tapēc ka esmu algebras un ģeometrijas ģēnijs Edited January 11, 2006 by Dj_erix Link to comment Share on other sites More sharing options...
Norek Posted January 15, 2006 Report Share Posted January 15, 2006 DEFINE a,b,c,d : integer; BEGIN d=(a+b+c)/3 writeln ('1. sk'); read a; writeln ('2. sk'); read b; writeln ('3. sk'); read c; write d; END; sorry, es pascalaa kaut ko programmeeju pirms 5 gadiem. doma ir pareiza, tikai neatceros iisto pieraxtu. slinkums skatiities ... taalaak pasham buus jaatiekgalaa. Link to comment Share on other sites More sharing options...
EDD Posted January 15, 2006 Report Share Posted January 15, 2006 norek, viss buutu baigi forshi (par pascala pierakstu neatbildu, man tas bija sen un nav taisniiba), tikai vinjam nemaz nevajadzeeja to triju skaitlju aritmeetisko videejo, bet tikai pateikt, kursh no tiem ir videejais peec veertiibas. Link to comment Share on other sites More sharing options...
Norek Posted January 15, 2006 Report Share Posted January 15, 2006 ok, padomaashu. Link to comment Share on other sites More sharing options...
Norek Posted January 15, 2006 Report Share Posted January 15, 2006 if a>b>c then write b; if a<b<c then write b; if b<a<c then write a; if b>a>c then write a; if b>c>a then write c; if b<c<a then write c; kaut kas taads ? Link to comment Share on other sites More sharing options...
SuperRembo Posted January 15, 2006 Author Report Share Posted January 15, 2006 My homeWork na 10 es to tomer izpildiju laika Link to comment Share on other sites More sharing options...
Dr. Pain Posted January 15, 2006 Report Share Posted January 15, 2006 if a>b>c then write b; if a<b<c then write b; if b<a<c then write a; if b>a>c then write a; if b>c>a then write c; if b<c<a then write c; kaut kas taads ? 1kaart, tavs kods ir galiigi garaam 2kaart, tu laikam neesi sapratius, ka kods nemaz nav vajadziigs. ir vaajdziiga diagramma, kas ataino to, kaa jaaraksta skripts (kaukaada UML vai kaa vinju tur sauca) 3kaart, tikko ieraudziiju SR poustu. Tas, ka tu ieliec suudiigu probleemu un peec tam pats vinju atrisini, neparaada to, ka esi kruts. Tas tikai paraada to, ka esi pilniigs idiots, jo 1) tu saakumaa shitik vieglu probleemu nespeeji pats atrisinaat 2) tu lielies ar shitik vieglas probleemas atrisinaashanu p.s. programeeshana galiigi nav domaata prieksh SR Link to comment Share on other sites More sharing options...
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