Liztikz* Posted October 14, 2009 Report Share Posted October 14, 2009 Yo. es nesaprotu sыdu par monфmiem, yo. [ ] tвtad, kвds gudrвks varзtu atrisinвt рos 2 piemзrus? 0,5(1,6a-2,5b)+1,2(-1,2a-0,8b) -6,2(x-5)+3(x- trоs ceturtвs) 3 -- 4 trоs ceturtвs Link to comment Share on other sites More sharing options...
reiniz.lv Posted October 14, 2009 Report Share Posted October 14, 2009 (edited) Neviena "=" zīme, un no 3 nezināmajiem dots 1? Tas jau ir unreal. Oh, yeah. My fault. 2 piemēri. Edited October 14, 2009 by reiniz.lv Link to comment Share on other sites More sharing options...
w4p1337 Posted October 14, 2009 Report Share Posted October 14, 2009 0,5(1,6a-2,5b)+1,2(-1,2a-0,8b) -6,2(x-5)+3(x- trīs ceturtās) -0,64a-2,21b -3.2x+33.25 vai pareizi? Link to comment Share on other sites More sharing options...
Liztikz* Posted October 14, 2009 Author Report Share Posted October 14, 2009 waplet, man vaig to pašu darbību kā tika atvērta iekava. Tom, no i`m not. http://bildites.lv/images/udlwt4bmnxxbte140ij.png reini, kurā kl ej, 5? 7 kl viela. Link to comment Share on other sites More sharing options...
w4p1337 Posted October 14, 2009 Report Share Posted October 14, 2009 iekavas atver šādi a(b+c)= a*b + a*c Link to comment Share on other sites More sharing options...
Liztikz* Posted October 14, 2009 Author Report Share Posted October 14, 2009 to es zinu, bet tu man uzraksti kā TU atvēri tajā piemērā iekavas, besis domāt. stūlbā algebra. Link to comment Share on other sites More sharing options...
GEAR Posted October 14, 2009 Report Share Posted October 14, 2009 man gan liekas a+b*a+c Link to comment Share on other sites More sharing options...
w4p1337 Posted October 14, 2009 Report Share Posted October 14, 2009 0,5(1,6a-2,5b)+1,2(-1,2a-0,8b) 0,5*1,6a-0,5*2.5b+1,2*(-1,2a)+1,2*(-0,8b) Link to comment Share on other sites More sharing options...
Liztikz* Posted October 14, 2009 Author Report Share Posted October 14, 2009 paldies waplet, varat lokot. Link to comment Share on other sites More sharing options...
ngEAr Posted October 14, 2009 Report Share Posted October 14, 2009 (edited) 0,5(1,6a-2,5b)+1,2(-1,2a-0,8b) -6,2(x-5)+3(x- trīs ceturtās) 0.8a - 1.25b - 1.44a - 0.96b = -0.64a - 2.21b -6.2x + 31 + 3x - 2.25 ; -3.2x = 28.75 zabej , Edited October 14, 2009 by ngEAr Link to comment Share on other sites More sharing options...
Asijs Posted October 15, 2009 Report Share Posted October 15, 2009 nebutu tagad jaiet uz skolu, butu izrekinajis. man pasam jaraksta kontrikis par monomiem... Link to comment Share on other sites More sharing options...
Hivemind Posted October 15, 2009 Report Share Posted October 15, 2009 psc kaut ko vel vienkāršāku nebiju redzējis. Aprēķiniet determinantu Det [{1,2,3,0}, {2,2,1,0},{3,3,5,2},{2,1,0,6}] divos veidos: a) izmantojiet Laplasa teorēmu, izvēloties visizdevīgāko rindu vai kolonu, ar uzlaboto Gausa metodi, pārkārtojot rindas un/vai kolonas, lai ietaupītu dažas darbības. Rezultātu pārbaudiet ar WolframAlpha. Kāds mosh izpilda manu mājas darbu , gribēšu redzēt cik cilvēki ir spējīgi uz to. Link to comment Share on other sites More sharing options...
macho Posted October 15, 2009 Report Share Posted October 15, 2009 tikai tagad es saprotu cik atbilstošs ir member title liztikam. Link to comment Share on other sites More sharing options...
reiniz.lv Posted October 15, 2009 Report Share Posted October 15, 2009 Ja domā, ka neesmu šito mācījies, u sux, `cause esmu augstāk par 7 klasi. ;D Vakar galvā šis tas bija ieperinājies. ALARMALARMALARMALARM. Link to comment Share on other sites More sharing options...
novijas Posted October 15, 2009 Report Share Posted October 15, 2009 Link to comment Share on other sites More sharing options...
samuray Posted October 15, 2009 Report Share Posted October 15, 2009 Aprēķiniet determinantu Det [{1,2,3,0}, {2,2,1,0},{3,3,5,2},{2,1,0,6}] divos veidos: a) izmantojiet Laplasa teorēmu, izvēloties visizdevīgāko rindu vai kolonu, ar uzlaboto Gausa metodi, pārkārtojot rindas un/vai kolonas, lai ietaupītu dažas darbības. Rezultātu pārbaudiet ar WolframAlpha. Kāds mosh izpilda manu mājas darbu , gribēšu redzēt cik cilvēki ir spējīgi uz to. ai, kur tas laiks, kad matricām determinantus rēķināju. 2 gadi jau riņķī, ņihuja neatceros. Link to comment Share on other sites More sharing options...
Hivemind Posted October 15, 2009 Report Share Posted October 15, 2009 Nu es viņu ņēmu fucking 12 klasē, tagad arī pēc 2vu gadu pauzes bija biškin japalauza galva Link to comment Share on other sites More sharing options...
mader Posted October 15, 2009 Report Share Posted October 15, 2009 determinantu aprēķināšana jau nu noteikti nebūtu tas grūtākais ko piedāvāt ... Link to comment Share on other sites More sharing options...
Liztikz* Posted October 15, 2009 Author Report Share Posted October 15, 2009 jaun sen vaidzēja būt lokotam, dabūju ieskaitīts un esmu priecīgs, bļe. Link to comment Share on other sites More sharing options...
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