FanTiik Posted June 15, 2009 Report Share Posted June 15, 2009 (edited) Labdien man ir problema ar sms acc visu istaisiju pec sis pamaciibas SMS ACC: 1:Atveram failu acc.php 2:Atrodam 27 lîniju 3:Ievadam savu mysql paroli un lietotâjvârdu 4:Atrodam 28 lîniju 5:Ievadam amxbans datubâzes vârdu 6:Veram ciet un ejam uz phpmyadmin 7:Amxbans datubâzee izveidojam jaunu tabulu codes ar vienu Field. (P.S izlaidiet 7 un 8 punktu tad ja jau esat ustaadiijushi sms unban vai sms nick reg skriptus) 8:Field vardu liekam code , type text , unicode utf8 un burtu daudzumu liekam 10 9:Talak ejam uz fortumo.lv , izveidojam jaunu pakalpojumu Advanced un beigâs skripta adresi liekam http://www.tavalapa.lv/code.php 10:Viss ir padariits. 11: Ja veelies lai kads neuzmin kods.php vardu un nedabu visus kodus bezmaksas tad izdoma vinjam pec iespejas sarezhgjitaku vardu! bet viss laik skrien ara Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\acc\clean.php on line 6 palidzat ludzu ka es varu no vinja tikt valja un ko man vaig rakstit phpmyadmin pareizi lai nebutu sitadas fi4as Edited June 15, 2009 by FanTiik Link to comment Share on other sites More sharing options...
kong1 Posted June 15, 2009 Report Share Posted June 15, 2009 (edited) šis scripts nekam neder vari tālāk mocīties ar šo! + Iesaku izmantot smadzenes , ja gribi normālu smsacc Edited June 15, 2009 by kong1 Link to comment Share on other sites More sharing options...
Lancom Posted June 16, 2009 Report Share Posted June 16, 2009 (edited) $result = mysql_fetch_assoc(mysql_query("SELECT code FROM codes WHERE code = '$kodinsh'")); на $result = mysql_fetch_assoc(mysql_query("SELECT code FROM code WHERE code = '$kodinsh'")); SQL CODE CREATE TABLE `code` ( `code` TEXT( 10 ) NOT NULL ) CHARACTER SET = latin1 Edited June 16, 2009 by Lancom Link to comment Share on other sites More sharing options...
FanTiik Posted June 16, 2009 Author Report Share Posted June 16, 2009 (edited) на $result = mysql_fetch_assoc(mysql_query("SELECT code FROM code WHERE code = '$kodinsh'")); SQL CODE CREATE TABLE `code` ( `code` TEXT( 10 ) NOT NULL ) CHARACTER SET = latin1 Lancom es visu ka tu paradii izdariju bet tas pats nekas neizmanas varbut tu nepareizo $result = mysql_fetch_assoc(mysql_query("SELECT code FROM code WHERE code = '$kodinsh'")); ieliki? jo vinji ir vienadi Edited June 16, 2009 by FanTiik Link to comment Share on other sites More sharing options...
dulais Posted June 16, 2009 Report Share Posted June 16, 2009 (edited) Ja tu nepamanīji viņš nomainīja vienu burtu un tam visam ir jaiet, ja tev neiet tad tu kaut ko dari nepareizi, $result = mysql_fetch_assoc(mysql_query("SELECT code FROM codes WHERE code = '$kodinsh'")); uz $result = mysql_fetch_assoc(mysql_query("SELECT code FROM code WHERE code = '$kodinsh'")); Edited June 16, 2009 by dulais Link to comment Share on other sites More sharing options...
kRi Posted June 16, 2009 Report Share Posted June 16, 2009 http://www.techpoint.lv/lv/smscenter/downloads/ Link to comment Share on other sites More sharing options...
FanTiik Posted June 16, 2009 Author Report Share Posted June 16, 2009 (edited) nu ieladeju es no ta techpoint to scriptu visu izdariju un ar tas pats erors iejeju phpmyadmin istaisu amxdatubaze code un ta pat man sitas erors Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\reg\clean.php on line 6 Neko nesaprotu palidzat man luudzu skype emilio5446 Edited June 16, 2009 by FanTiik Link to comment Share on other sites More sharing options...
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