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Cracky

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  1. ja nezinu kas par vainu neraksti gaili! MySQL tabulu esmu uztaisijis!! viss ir! bet met araa erroru!!
  2. tu domaaa tipa ieks phpmyadmin?
  3. Sveiki man ir probleema ar webshopu meginaaju izlabot jebkaadigi nu nemaaku!! Kr4 pie lietas. Es aizsutu izzinu atnak kods ievadu to ailee un uzpiezu Apstiprinaatb et man uzmet saadu erroru!! Warning:mysql_result(): Supplied argument is not a valid MySQL result resource in C:\AppServ\www\sms\smscw.phpon line 82 es atveru tur man taa 82 line iskataas saadi! if(mysql_result(mysql_query("SELECT COUNT(*) FROM code WHERE code = '$code'"),0,'COUNT(*)') > 0){ Ludzu kads vareetu paliidzeet! Varetu pateikt ludzu ko darit vajag???
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