Get5 Posted March 17, 2008 Report Share Posted March 17, 2008 (edited) Man tada problema kip ar calladmin script cakarejos un kad ieeju loga localhost/bla/bla/bla un uzeju calladmin kad pasaukt var man paradas apaksa sads te uzraksts Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'pmremote'@'localhost' (using password: NO) in C:\AppServ\www\index.php on line 208 $mysql[host] = "sh-lr.oo.lv"; $mysql[user] = "pmremote" $mysql[pwd] = ""; $mysql[db] = "projects"' $mysql[table] = "version"' $this[project] = "AdminCall"; $this[version] = "1.0"; $con = mysql_connect($mysql[ip], $mysql[user], $mysql[pwd]) or error(""); (SI IR TA line 208) mysql_select_db($mysql[db], $con) or error(""); $result = mysql_query("SELECT version , status FROM ".$mysql[table]." WHERE projectname = '".$this[project]."'"); velejos dzirdet kadas domas ka to novers vai mainit lai neraditos error Saku jau pieprieks paldies... Edited March 17, 2008 by Get5 Link to comment Share on other sites More sharing options...
*jancis38* Posted March 17, 2008 Report Share Posted March 17, 2008 (edited) fak u, ou šit. -> aa fak u, ou šit vīdeo. (: Edited March 17, 2008 by *jancis38* Link to comment Share on other sites More sharing options...
duplets Posted March 17, 2008 Report Share Posted March 17, 2008 Esmu stipri pārliecināts, ka veido uz locālā tad arī try this: $mysql[host] = "localhost"; $mysql[user] = "root" $mysql[pwd] = "tavs pass"; $mysql[db] = "projects"' $mysql[table] = "version"' $this[project] = "AdminCall"; $this[version] = "1.0"; or this: $mysql[host] = "localhost"; $mysql[user] = "pmremote" $mysql[pwd] = "tavs pass"; $mysql[db] = "projects"' $mysql[table] = "version"' $this[project] = "AdminCall"; $this[version] = "1.0"; nu notekti aizies... Link to comment Share on other sites More sharing options...
Get5 Posted March 17, 2008 Author Report Share Posted March 17, 2008 (edited) $mysql[host] = "localhost"; $mysql[user] = "root" (si ir line 200) $mysql[pwd] = "tavs pass"; $mysql[db] = "projects"' $mysql[table] = "version"' $this[project] = "AdminCall"; $this[version] = "1.0"; or this: $mysql[host] = "localhost"; $mysql[user] = "pmremote" (si ir line 200) $mysql[pwd] = "tavs pass"; $mysql[db] = "projects"' $mysql[table] = "version"' $this[project] = "AdminCall"; $this[version] = "1.0"; nu notekti aizies... Neee diemzel nee neiet, pameginaju abus neviens neiet un rada Parse error: parse error, unexpected T_VARIABLE in C:\AppServ\www\index.php on line 200 abiem diviem..... PS. jancis38 ej dirs* un beidz spamot... PSS. tas video bija nirdzigs...... :/ Edited March 17, 2008 by Get5 Link to comment Share on other sites More sharing options...
duplets Posted March 17, 2008 Report Share Posted March 17, 2008 pats vainīgs, ka aiz $mysql[user] = "root" nēsi ieliecis ķeksi - ; Link to comment Share on other sites More sharing options...
Get5 Posted March 17, 2008 Author Report Share Posted March 17, 2008 (edited) Ops aizmirsu pa tiem keksiem (nezinu ko vini dod) tadel nekliku..... Paldies duplets tagad to erroru nemet vairs..... tik met citu bet gan jau tiksu gala kad atradisu kura line ta ir jo tas otrs scrit kk crazy sataisits Edited March 17, 2008 by Get5 Link to comment Share on other sites More sharing options...
duplets Posted March 17, 2008 Report Share Posted March 17, 2008 šeit: $mysql[db] = "projects"' $mysql[table] = "version"' Link to comment Share on other sites More sharing options...
*jancis38* Posted March 17, 2008 Report Share Posted March 17, 2008 PSS. tas video bija nirdzigs...... :/ fak jā, es tev devu linku, kur savu erroru varēji izlabot. Neesmu vainigs, ka nēesi spējis ievadīt pareizus datus. Link to comment Share on other sites More sharing options...
Get5 Posted March 17, 2008 Author Report Share Posted March 17, 2008 man tas links neiet tik tur kur video so, es Link to comment Share on other sites More sharing options...
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