bloodlord Posted May 29, 2007 Report Share Posted May 29, 2007 (edited) mekleju kadu cilveeku/s ,kas kaut ko saprot no paskaalja , paskalja asamblera un palidzeetu man uztaisiit paris darbus , parada nepalikshu Aizmirsu piebilst ka butu forshi ja butu pierakstiiti ari komentari , ko kas dara. ps : JA NEVARI PALIDZEET VARI TE NEKO NERAKSTIT 1) kaut kas saistiits ar LOOP Atrast visu pāra skaitļus intervāla no m lidz n summu , kur m un n ievada lietotājs. 2) tjip asm , lidz 26 Aizpildīt masīvu ar nepāra skaitļiem , kas sākas no 1 un atrast masīva elementu summu Edited May 29, 2007 by bloodlord Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 29, 2007 Report Share Posted May 29, 2007 (edited) mekleju kadu cilveeku/s ,kas kaut ko saprot no paskaalja , paskalja asamblera un palidzeetu man uztaisiit paris darbus , parada nepalikshu ps : JA NEVARI PALIDZEET VARI TE NEKO NERAKSTIT 1) kaut kas saistiits ar LOOP Atrast visu pāra skaitļus intervāla no m lidz n summu , kur m un n ievada lietotājs. 2) tjip asm , lidz 26 Aizpildīt masīvu ar nepāra skaitļiem , kas sākas no 1 un atrast masīva elementu summu Varu palidzet, bet isti nesaprotu, ko tev vajag? kada pskala? turbo? un pricom asamplers? Beefs nu primais un otrais nevajag pat ciklu, bet ok 1) res :=0; for x:=m to n do if not odd( then inc(res,; 2) for x:=1 to 26 do mas[x]:=x*2-1; Edited May 29, 2007 by 0xDEAD BEEF Link to comment Share on other sites More sharing options...
bloodlord Posted May 29, 2007 Author Report Share Posted May 29, 2007 man vajag lai uztaisa abas programmas , vienagla kada paskaali , un cik atceros tad tas otrais bija jataisa ar asm , bet varbuut ari kludos Link to comment Share on other sites More sharing options...
Norek Posted May 29, 2007 Report Share Posted May 29, 2007 Ja pareizi sapratu, tad vajag atrast visu pāra skaitļu summu, intervālā no m līdz n. Ja lielotājs ievada m = 1 un n = 10, tad 2+4+6+8 būs pāru skaitļu summa intervālā no 1 līdz 10. Am I right ? Cik steidzami Tev šo vajag ? Link to comment Share on other sites More sharing options...
bloodlord Posted May 29, 2007 Author Report Share Posted May 29, 2007 nu itka 4dien vajadzeetu nodot Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 29, 2007 Report Share Posted May 29, 2007 (edited) man vajag lai uztaisa abas programmas , vienagla kada paskaali , un cik atceros tad tas otrais bija jataisa ar asm , bet varbuut ari kludos Blja nu izdoma, ko tev vajag, a to pizdi dabusi! pirma programa turbo paskala - uses crt; var m,n,x,res:integer; begin write('Ievadiet m un n:'); readln(m,n); if not (m<n) then begin writeln('m jabut mazak par n!');halt; end; res:=0; for x:=m to n do if not odd(x ) then inc(res,x ); writeln('rezultats ir ', res); end. Un par otro izdoma, ko tev isti vajag! Asamblera vai paskala. Un ja asamblera, tad nevaru palidzet ar ievadu un izvadu, jo tas asablers ir tik anarhaisks, ka man vina nemaz vairak nav, bet varu iedot kodu paskala, ko vari parverst asamblera un pec tam izpipe, ka uztaisit ievadu un izvadu taja miskaste. Beefs Edited May 29, 2007 by 0xDEAD BEEF Link to comment Share on other sites More sharing options...
bloodlord Posted May 29, 2007 Author Report Share Posted May 29, 2007 tikko uzzinaju , 1ais ir jataisa ar kaut kadu loop ciklu , un abi divi ir jataisa paskalja asamblera.. Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 29, 2007 Report Share Posted May 29, 2007 tikko uzzinaju , 1ais ir jataisa ar kaut kadu loop ciklu , un abi divi ir jataisa paskalja asamblera.. iedo piemeru ar ievadu un izvadu. parejo jau izstukosu! Beefs Link to comment Share on other sites More sharing options...
bloodlord Posted May 29, 2007 Author Report Share Posted May 29, 2007 te buus viens uzdevums . lietpotaajs ievada veselos skaitljus a un x, kaa arii tiek ievadiits f(} program funkcija; uses crt; var x,a,f:integer; label l1,l2,l3; begin clrscr; writeln ('a/x,x<-2'); writeln ('2x,-2<=x<=500'); writeln ('ax, x>500'); writeln('ievadiet x'); readln (; writeln ('ievadiet a'); readln (a); asm cmp x,-2; JNL l1 {x>=-2 iet uz l1} mov AX,a {x<-2} mov BX,1{reizinaam ax ar 1, lai buutu drosi, par dx saturu} imul BX mov BX,x idiv BX {(AX:BX)} mov f, AX JMP l3 l1:cmp x,-2 {x nav <-2, taatad -2<=x} JL l2 {x<=500} mov AX, 2 imul x mov f,AX JMP l3 l2:cmp x,500 JG l3 {x>500} mov AX, x mul a mov f,AX l3:end; writeln ('f(=',f) ; readln; end. Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 29, 2007 Report Share Posted May 29, 2007 te buus viens uzdevums . lietpotaajs ievada veselos skaitljus a un x, kaa arii tiek ievadiits f(} program funkcija; uses crt; var x,a,f:integer; label l1,l2,l3; begin clrscr; writeln ('a/x,x<-2'); writeln ('2x,-2<=x<=500'); writeln ('ax, x>500'); writeln('ievadiet x'); readln (; writeln ('ievadiet a'); readln (a); asm cmp x,-2; JNL l1 {x>=-2 iet uz l1} mov AX,a {x<-2} mov BX,1{reizinaam ax ar 1, lai buutu drosi, par dx saturu} imul BX mov BX,x idiv BX {(AX:BX)} mov f, AX JMP l3 l1:cmp x,-2 {x nav <-2, taatad -2<=x} JL l2 {x<=500} mov AX, 2 imul x mov f,AX JMP l3 l2:cmp x,500 JG l3 {x>500} mov AX, x mul a mov f,AX l3:end; writeln ('f(=',f) ; readln; end. karoce - panejm tad pasaklu, nokomile debug versiju. ieliec breakpointu un tad, kad nobreiko, tad atver cpu un redzesi asm kodu. nokope visu, izmet lieku un bus tev asm kods vajadzigas! Beefs p.s. es to nevaru izdarit, jo man nav pieejams paskals. varu tikai uzrakstit kodu paskala. Link to comment Share on other sites More sharing options...
bloodlord Posted May 30, 2007 Author Report Share Posted May 30, 2007 nja ,butu labi ja es kaut ko saprastu no tava rakstiita Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 nja ,butu labi ja es kaut ko saprastu no tava rakstiita tu tacu datorus stude.. :/ tev jasaprot! Karoce - ta programa kura programe, vina var izveleties nokompilet debug rezima programu. Tu maki vispar kompilet un palaist programu.. :/ Ka tad tu ucukam paradisi to kodu? Beefs Link to comment Share on other sites More sharing options...
mader Posted May 30, 2007 Report Share Posted May 30, 2007 karoce - panejm tad pasaklu, nokomile debug versiju. ieliec breakpointu un tad, kad nobreiko, tad atver cpu un redzesi asm kodu. nu shito es nesapratu paareejais nebij tik gruuts PS beefi negribi paliidzeet scaraa uztaisiit programminju ? Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 nu shito es nesapratu paareejais nebij tik gruuts PS beefi negribi paliidzeet scaraa uztaisiit programminju ? sorry.. sadirsu.. karoce options debuger jaiekekse standalone sebuging. tad tool-> turbo debuger. tad view -> cpu un rezultats PROGRAM.10: for x:=m to n do if not odd(x ) then inc(res,x ); cs:00B3 A15400 mov ax,[0054] cs:00B6 8946FE mov [bp-02],ax cs:00B9 A15200 mov ax,[0052] cs:00BC 3B46FE cmp ax,[bp-02] cs:00BF 7F1F jg PROGRAM.11 (00E0) cs:00C1 A35600 mov [0056],ax cs:00C4 EB04 jmp 00CA cs:00C6 FF065600 inc word ptr [0056] cs:00CA A05600 mov al,[0056] cs:00CD D0E8 shr al,1 cs:00CF 7207 jb 00D8 cs:00D1 A15600 mov ax,[0056] cs:00D4 01065800 add [0058],ax cs:00D8 A15600 mov ax,[0056] cs:00DB 3B46FE cmp ax,[bp-02] cs:00DE 75E6 jne 00C6 nav erti, tapec parakstisim bisku kodu! nu re - te viss skaidri redzam! ) PROGRAM.10: for x:=m to n do cs:00B3 A15400 mov ax,[0054] //n cs:00B6 8946FE mov [bp-02],ax cs:00B9 A15200 mov ax,[0052] //m cs:00BC 3B46FE cmp ax,[bp-02] cs:00BF 7F1F jg PROGRAM.13 (00E0) cs:00C1 A35600 mov [0056],ax //x:=m cs:00C4 EB04 jmp PROGRAM.11 (00CA) cs:00C6 FF065600 inc word ptr [0056] //x:=x+1 PROGRAM.11: if not odd(x ) then cs:00CA A05600 mov al,[0056] cs:00CD D0E8 shr al,1 // al = x / 2 cs:00CF 7207 jb 00D8 //ja nav odd, tad ejam uz cikla beigam PROGRAM.12: inc(res,x ); cs:00D1 A15600 mov ax,[0056] //ax = x cs:00D4 01065800 add [0058],ax //res = res + x (ax) cs:00D8 A15600 mov ax,[0056] //cikla beigas. ax = x cs:00DB 3B46FE cmp ax,[bp-02] //vai ax = n??? btw n tiek tagad glabats steka! cs:00DE 75E6 jne 00C6 Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 tagad no musu koda aiznemsimies vertigo ifu! mov al,x shr al,1 jb notodd mov ax,x add res,ax :notodd un izdomasim loopu mov cx,n //ieliekam cx n dec cx,m //atnemam no cx m :loops loop loops //loopojam kamer cx nav 0le! ) tagad saliksim visu kopa! asm mov res,0 mov ax,m mov x,ax mov cx,n sub cx,m inc cx loops: mov ax,x shr al,1 jb notodd mov ax,x add res,ax notodd: inc x loop loops end; Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 jaatdzist, ka tas ir viss tizlakais veids, kada var lietot loopu.. (( var m,n,x,res:integer; label loops,notodd; begin write('Ievadiet m un n:'); readln(m,n); if not (m<n) then begin writeln('m jabut mazak par n!');halt; end; res:=0; for x:=m to n do if not odd(x ) then inc(res,x ); writeln('rezultats ir ', res); asm mov res,0 mov ax,m mov x,ax mov cx,n sub cx,m inc cx loops: mov ax,x shr al,1 jb notodd mov ax,x add res,ax notodd: inc x loop loops end; writeln('rezultats asma ir ', res); end. Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 (edited) Te bus otra proga. Karoce PROGRAM.5: res:=0; cs:0030 31C0 xor ax,ax cs:0032 A35400 mov [0054],ax PROGRAM.6: for x:=1 to 26 do cs:0035 C70652000100 mov word ptr [0052],0001 cs:003B EB04 jmp PROGRAM.8 (0041) cs:003D FF065200 inc word ptr [0052] PROGRAM.8: mas[x]:=x*2-1; cs:0041 A15200 mov ax,[0052] cs:0044 D1E0 shl ax,1 //x* 2 cs:0046 48 dec ax //x-1 cs:0047 8B3E5200 mov di,[0052] cs:004B D1E7 shl di,1 cs:004D 89855400 mov [di+0054],ax PROGRAM.9: inc(res,mas[x]); cs:0051 8B3E5200 mov di,[0052] cs:0055 D1E7 shl di,1 cs:0057 8B855400 mov ax,[di+0054] cs:005B 01065400 add [0054],ax PROGRAM.10: end; cs:005F 833E52001A cmp word ptr [0052],001A cs:0064 75D7 jne 003D un rezultata kods! var x,res:integer; mas:array[1..26] of integer; label loops,notodd; begin res:=0; for x:=1 to 26 do begin mas[x]:=x*2-1; inc(res,mas[x]); end; writeln('rezultats ir ', res); asm mov res,0 mov cx,26 loops: mov ax,cx shl ax,1 dec ax mov di,cx shl di,1 mov [di+offset mas],ax add res,ax loop loops end; writeln('rezultats asma ir ', res); end. p.s. es tikai nezinu, vai tas asma klucis pareizi aizpilda masivu... vajadzetu kaut kadu kodinu vel piemest, kas izvada to masivu uz ekrana, bet man slinkums! Edited May 30, 2007 by 0xDEAD BEEF Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 (edited) karoce vajag bisku pielabot sito rindinu mov [di+offset mas],ax jabuut mov [di+offset mas-2],ax jo uz cx 0 sitais kods neiziet un tapec neaizpilds masiva 0to elemtnu Beefs edit beigas vari piemest for x:=1 to 26 do write(mas[x],' '); tad redzesi, kas ir taja masiva salikts ieksa! Parliecibas pec gan tad vajadzetu izkomentet augsejo kodu, kas darbojas ar masivu, lai butu ticamibas moments, ka masivu aizpilda asm nevis paskala kods. EDIT: un vispar tev pizdata paveicas, ka man uz kompja vel paskals vecais metajas! ja?! Edited May 30, 2007 by 0xDEAD BEEF Link to comment Share on other sites More sharing options...
bloodlord Posted May 30, 2007 Author Report Share Posted May 30, 2007 paldies , kaut kad velak iechekoshu tos darbus Link to comment Share on other sites More sharing options...
mader Posted May 30, 2007 Report Share Posted May 30, 2007 pss biifis malacis tad paliidzeesi progu uztaisiit ? Link to comment Share on other sites More sharing options...
DJ MUman Posted May 30, 2007 Report Share Posted May 30, 2007 (edited) Beefijs Edit: Hmm? vajadzēja būt citam smailijam. Ā ir divi smailiji un abiem ir vienāds nosaukums? Edited May 30, 2007 by DJ MUman Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted May 30, 2007 Report Share Posted May 30, 2007 pss biifis malacis tad paliidzeesi progu uztaisiit ? veljoprojam nezinu, kas ir scras, bet ja uzrakstisi, ko vajag uztaisit, tad varbut kaut ko zidoamsu! Beefs Link to comment Share on other sites More sharing options...
mader Posted May 31, 2007 Report Share Posted May 31, 2007 (edited) Beefs Kr4 scar ir programmeeshanai domaata proga pamataa uz pascall baazes, bet nu daudz piemeerotaaka darbiibai ar win... tb var image lasiit, rakstiit man caur vinju vajadzeetu uztaisiit progu kas nolasa skaitljus no skaitlju regenereetaaja un ievada laukaa !!! diemzeel nokopeet vinjus nevar un tad jau arii tev paliidziibu neprasiitu ! PS. SCAR ir lv izveidota proga un vinju var inetaa novilkt !! Edited May 31, 2007 by mader Link to comment Share on other sites More sharing options...
worm Posted May 31, 2007 Report Share Posted May 31, 2007 beef, njemu tevi darbaa par bustera koderi algaa alinsh Link to comment Share on other sites More sharing options...
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