rizhaaa Posted June 24, 2009 Report Share Posted June 24, 2009 Sveiki, man te aizkeeries viens fizikas uzdevums, kuru pac es nevaru atrisinaat pashu uzdevumu varat novilkt - http://yy.lv/upload/index.php?ACT=4&f=54077&ext=JPG Tas kas izpildiis, dabuus kadu latinju ( sho izpildiito uzdevumu man vajag shodien lidz ~ 01:00 ) paldies visiem Link to comment Share on other sites More sharing options...
Domino Posted June 24, 2009 Report Share Posted June 24, 2009 pasties klade forumulas un lieta darkta Link to comment Share on other sites More sharing options...
Kuilis Posted June 24, 2009 Report Share Posted June 24, 2009 Nu psc, kas tu skaitļus pamatmērvienībās nevari pārveidot un salikt formulās?.. Link to comment Share on other sites More sharing options...
rizhaaa Posted June 24, 2009 Author Report Share Posted June 24, 2009 man sheit nekaadu klazhu, un formulu nav Link to comment Share on other sites More sharing options...
0xDEAD BEEF Posted June 24, 2009 Report Share Posted June 24, 2009 S ir laukums, vai ne? Tada gaidijuma, ja zudumi ir 2%, tad .. btw U ir nevis kw, bet gan kV! Lol: Tatad kopeja kabela pretestiba R = q * 3 * 10^6 (300km) / S ir paga U = 200 000 (200kV) = 2 * 10^5 P = 600 000 000 (500MW) = 6 * 10^8 P + zudumi = 6 * 10*8 * 1.02 (+2%) Ista vajadziga jauda = (es gan domaju, ka nevis 2% bet 20%, bet nu ok) P = 6.12 * 10*8 P = U * I I = P / U I = 6.12 * 10*8 / 2 * 10^5 = 3.06 * 10^3 U = I * R R = U / I R = 2 * 10^5 / 3.06 * 10^3 =~0.6535 * 10^2 = ~65.35 R = q * l / S S = q * l / R S = 0.0175 * 300 000 / 65.35 = ~80.36mm^2 Izskatas ticama vertiba, jo ja laukums ir tads, tad diametrs sanaktu pi * R^2 = 10mm. Reals kabela resnums! Divi alini no tevis gadaa centra! Beefs Link to comment Share on other sites More sharing options...
rizhaaa Posted June 24, 2009 Author Report Share Posted June 24, 2009 thank u divi alini no manis Link to comment Share on other sites More sharing options...
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